5x^2+20/10x^2+40

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Solution for 5x^2+20/10x^2+40 equation: 


x in (-oo:+oo)

5*x^2+(20/10)*x^2+40 = 0

7*x^2 = -40 // : 7

x^2 = -40/7

x belongs to the empty set

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